6v^2-8=0

Solution for 6v^2-8=0 equation:

6v^2-8=0

a = 6; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·6·(-8)
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{3}}{2*6}=\frac{0-8\sqrt{3}}{12}
=-\frac{8\sqrt{3}}{12}
=-\frac{2\sqrt{3}}{3}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{3}}{2*6}=\frac{0+8\sqrt{3}}{12}
=\frac{8\sqrt{3}}{12}
=\frac{2\sqrt{3}}{3}
$